反序列化属性作为使用JSON.NET的ExpandoObject [英] Deserialize a property as an ExpandoObject using JSON.NET

查看:1160
本文介绍了反序列化属性作为使用JSON.NET的ExpandoObject的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

例如,有像下一个对象:

For example, there's an object like the next one:

public class Container
{
   public object Data { get; set; }
}

和它的使用是这样的:

Container container = new Container
{
    Data = new Dictionary<string, object> { { "Text", "Hello world" } }
};

如果我反序列化从序列上面的实例中,获得的数据JSON字符串属性,即使我提供 ExpandoObjectConverter ,这不是反序列化作为一个 ExpandoObject

If I deserialize a JSON string obtained from serializing the above instance, the Data property, even if I provide the ExpandoObjectConverter, it's not deserialized as an ExpandoObject:

Container container = JsonConvert.Deserialize<Container>(jsonText, new ExpandoObjectConverter());



如何反序列化与匿名对象指定一个类属性,或者至少不具体类型为 ExpandoObject

How can I deserialize a class property assigned with an anonymous object, or at least, not concrete type as an ExpandoObject?

有人回答,我可以只使用动态对象。这不会为我工作。我知道我可以走这条路,而是因为我需要一个ExpandoObject不是这种情况。
谢谢

其他一些用户回答我可以反序列化一个JSON字符串转换成 ExpandoObject 。这不是这个问题的目的。我需要反序列化具有动态性的具体类型。在JSON字符串该属性可能是一个关联数组

Some other user answered I could deserialize a JSON string into an ExpandoObject. This isn't the goal of this question. I need to deserialize a concrete type having a dynamic property. In the JSON string this property could be an associative array.

推荐答案

试试这个:

Container container = new Container
{
    Data = new Dictionary<string, object> { { "Text", "Hello world" } }
};

string jsonText = JsonConvert.SerializeObject(container);

var obj = JsonConvert.DeserializeObject<ExpandoObject>(jsonText, new ExpandoObjectConverter());



我发现,这样做让我的 ExpandoObject 从调用 DeserializeObject 。我想与您所提供的代码的问题是,当你在提供一个 ExpandoObjectConverter ,你问 Json.Net 反序列化集装箱,所以我会想象, ExpandoObjectConverter 不被使用。

I found that doing this got me an ExpandoObject from the call to DeserializeObject. I think the issue with the code you have provided is that while you are supplying an ExpandoObjectConverter, you are asking Json.Net to deserialize a Container, so I would imagine that the ExpandoObjectConverter is not being used.

编辑:

如果我装点数据财产 [JsonConverter(typeof运算(ExpandoObjectConverter))] ,并使用代码:

If I decorate the Data property with [JsonConverter(typeof(ExpandoObjectConverter))] and use the code:

var obj = JsonConvert.DeserializeObject<Container>(jsonText);



然后数据属性被反序列化到 ExpandoObject ,而 OBJ 集装箱

Then the Data property is deserialized to an ExpandoObject, while obj is a Container.

这篇关于反序列化属性作为使用JSON.NET的ExpandoObject的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆