我怎么能告诉我们，如果一个元素在Microsoft UI自动化一个PropertyCondition相匹配？ [英] How can I tell if an element matches a PropertyCondition in Microsoft UI Automation?

问题描述

我试图找到一个GridView的特定行的AutomationElement（所以有很多相同的元素）。我遍历行中的元素，我想用一个匹配，看是否有特定的元素，我传递给它的条件相匹配。 。我开始用简单的PropertyConditions

I'm trying to find an AutomationElement in a particular row of a GridView (so there are many identical elements). I'm iterating over the elements in the row, and I'd like to use a matcher to see if a particular element matches the Condition I'm passing to it. I'm starting with simple PropertyConditions.

下面是我的测试：

[TestFixture]
public class ConditionMatcherBehaviour
{
    [Test]
    public void ShouldMatchAPropertyConditionByItsValue()
    {
        var conditionMatcher = new ConditionMatcher();
        var condition = new PropertyCondition(AutomationElement.ControlTypeProperty, ControlType.Pane);
        Assert.True(conditionMatcher.Matches(AutomationElement.RootElement, condition));
    }
}

和下面的代码：

public class ConditionMatcher : IMatchConditions
{
    public bool Matches(AutomationElement element, Condition condition)
    {
        var propertyCondition = (PropertyCondition) condition;
        return propertyCondition.Value.Equals(element.GetCurrentPropertyValue(propertyCondition.Property));
    }
}

不幸的是，测试失败。根元素（桌面）的ControlType确实ControlType.Pane，但奇怪的是PropertyCondition.Value50033。

Unfortunately the test fails. The ControlType of the root element (the desktop) is indeed ControlType.Pane, but bizarrely the PropertyCondition.Value is "50033".

任何想法，我怎么能考FindFirst中/的FindAll以外的PropertyCondition？

Any ideas as to how I can test a PropertyCondition outside of FindFirst / FindAll?

（我的解决方法是创建自己的条件类型，并测试代替，但我想确认我不是误解的东西/做一些愚蠢的。）

(My workaround is to create my own condition type and test that instead, but I'd like to check that I'm not misunderstanding something / doing something stupid.)

推荐答案

找到了。

public class ConditionMatcher : IMatchConditions
{
    public bool Matches(AutomationElement element, Condition condition)
    {
        return new TreeWalker(condition).Normalize(element) != null;
    }
}

不完全是显而易见的，但它同时适用于匹配和非匹配条件。感谢所有谁看了一下，思考了一下。希望这会帮助别人！

Not exactly obvious, but it works for both matching and non-matching conditions. Thanks to all who looked and thought about it for a bit. Hopefully this will help someone else!

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