二次贝塞尔曲线：Y坐标中给定X？ [英] Quadratic bezier curve: Y coordinate for a given X?

问题描述

我有一个的二次的贝塞尔曲线，我需要一个给定的X坐标贝塞尔曲线上的点的Y坐标。我知道，在纯数学这可以很容易做到，但我不知道是在C＃/ WPF有一个简单/另一种方式呢？是否有可能习惯于单点用C＃/ WPF绘制贝塞尔曲线，然后也许只是循环比较它们与给定的X坐标每个点的X坐标？ BTW的数学方法这将是很好知道哪一步了贝塞尔曲线的参数t已经被C＃/ WPF choosen？任何机会，以发现这一点？也许t的只是/缩放的步骤在t是1 /（P0，P2的距离）？ ！
非常感谢您的任何暗示。

I have a quadratic bezier curve and I need the Y coordinate of a point on the bezier curve for a given X coordinate. I know that in pure maths this can be easily done, but I'm wondering is there's a simple / another way for this in C# / WPF? Is it possible to get the single points used by C# / WPF for drawing the bezier curve and then maybe just loop them and compare the X coordinate of each point with the given X coordinate? BTW for the mathematical way it would be good to know which step for the parameter t of the bezier curve has been choosen by C# / WPF? Any chance to find this out? Probably t is just scaled by / steps for t are 1/(distance of P0 and P2) ? Thank you very much for any hint!

推荐答案

在Degrafa看看的贝塞尔Ÿ位于X算法。

Take a look at Degrafa Bezier Y at X Algorithm.

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