Rails的模型和QUOT;的before_filter"? [英] Rails model "before_filter"?
问题描述
我知道的before_filter是仅适用于Rails的控制器,但我想是这样的模式:任何时候在我的模型的方法被调用时,我想运行一个方法,决定调用的方法是否应该跑。从概念上讲,是这样的:
类网站<的ActiveRecord :: Base的
的before_filter:confirm_company
高清confirm_company
如果self.parent.thing ==假的?
返回false
结束
结束
DEF方法1
#do东西
结束
结束
所以,当我打电话@ website.method1,它会首先调用confirm_company,如果我返回false,将无法运行方法1。滑轨是否有这样的功能?我希望我只是错过了一些东西明显在这里...
类为MyModel
延长加载ActiveModel ::回调
define_model_callbacks:do_stuff
before_do_stuff:确认
高清do_stuff
run_callbacks:do_stuff做
#your code
结束
结束
DEF确认
#确认
结束
结束
我真的不知道这会的工作,但你可以尝试一下,因为我真的没有时间了。看看是:<一href="http://api.rubyonrails.org/classes/ActiveModel/Callbacks.html">http://api.rubyonrails.org/classes/ActiveModel/Callbacks.html
I know that before_filter is only for controllers in Rails, but I would like something like this for a model: any time a method in my model is called, I'd like to run a method that determines whether the called method should run. Conceptually, something like this:
class Website < ActiveRecord::Base
before_filter :confirm_company
def confirm_company
if self.parent.thing == false?
return false
end
end
def method1
#do stuff
end
end
So when I call @website.method1, it will first call confirm_company, and if I return false, will not run method1. Does Rails have functionality like this? I hope i'm just missing out on something obvious here...
class MyModel
extend ActiveModel::Callbacks
define_model_callbacks :do_stuff
before_do_stuff :confirm
def do_stuff
run_callbacks :do_stuff do
#your code
end
end
def confirm
#confirm
end
end
I'm really not sure this will work, but you can try it, as I really dont have time now. Take a look at that: http://api.rubyonrails.org/classes/ActiveModel/Callbacks.html
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