如何创建字典< INT，串>通过LINQ到XML？ [英] How to Create Dictionary<int, string> via LINQ to XML?

问题描述

我有下面的XML：

<FootNotes>
  <Line id="10306" reference="*"></Line>
  <Line id="10308" reference="**"></Line>
  <Line id="10309" reference="***"></Line>
  <Line id="10310" reference="****"></Line>
  <Line id="10311" reference="+"></Line>
</FootNotes>

和我有下面的代码，我得到一个词典<整型，字符串>（）对象为

and I have the following code where I'm to get a Dictionary<int, string>() object into

myObject.FootNotes 

，使每一行是一个键/值对

so that each Line is a Key/Value pair

var doc = XElement.Parse(xmlString);

var myObject = new
  {
      FootNotes = (from fn in doc
                       .Elements("FootNotes")
                       .Elements("Line")
                       .ToDictionary
                       (
                       column => (int) column.Attribute("id"),
                       column => (string) column.Attribute("reference")
                       )
                  )
  };

我不确定如何从XML进入对象这虽然。任何人都可以提出一个解决方案？

I am unsure how to get this from the XML into the object though. Can anyone suggest a solution?

推荐答案

您的代码几乎是正确的。试试这个微小的变化，而不是：

Your code is nearly correct. Try this slight variation instead:

FootNotes = (from fn in doc.Elements("FootNotes")
                           .Elements("Line")
             select fn).ToDictionary(
                 column => (int)column.Attribute("id"),
                 column => (string)column.Attribute("reference")
             )

我不认为从长远从...选择语法真的帮助很多在这里。我会用这个稍微简单的代码，而不是：

I don't think the long from ... select syntax really helps much here. I'd use this slightly simpler code instead:

Footnotes = doc.Descendants("Line").ToDictionary(
                e => (int)e.Attribute("id"),
                e => (string)e.Attribute("reference")
            )

不过你使用在你的示例代码匿名类型。您需要使用，如果你打算到这个对象返回给调用者的具体类型。

However you are using an anonymous type in your example code. You need to use a concrete type if you are planning to return this object to the caller.

var myObject = new SomeConcreteType
    {
        Footnotes = ....
    };

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