如何使用json.net（JObject / Jarray / Jtoken），并以最快的方式转换成类到字典？ [英] How to use json.net(JObject/Jarray/Jtoken) and convert to class in the fastest way into a dictionary?

问题描述

如何使用json.net（JObject / Jarray / Jtoken）并以最快的（性能）方式转换为类到字典？字典的键是json文件中的name。

How to use json.net(JObject/Jarray/Jtoken) and convert to class in the fastest(performance) way into a dictionary? the key of the dictionary is the sees "name" in the json file

任何人都可以帮助？

感谢alot！

seed.json
       {
          "Seed": [
                {
                    "name": "Cheetone",
                    "growthrate": 1,
                    "cost": 500
                },
                {
                    "name": "Tortone",
                    "growthrate": 8,
                    "cost": 100
                }
            ],
        }


    public class SoilStat
    {
        public int growthRate;
        public int cost;
    }

    public class DataLoader : MonoSingleton<DataLoader>
    {
        public string txt;
        Dictionary<string, SoilStat> _soilList = new Dictionary<string, SoilStat>();

        JObject rawJson = JObject.Parse(txt);

        ???
    }

推荐答案

您想使用 SelectTokens 选择您感兴趣的JSON部分，然后对这些位进行反序列化。因此：

A simple way to do what you want is to use SelectTokens to pick out the portions of JSON of interest to you, then just deserialize those bits. Thus:

        var rawJson = JObject.Parse(txt);
        var _soilList = rawJson.SelectTokens("Seed[*]").ToDictionary(t => t["name"], t => t.ToObject<SoilStat>());

一个更复杂的解决方案是创建 DTO对象进行反序列化，然后将它们映射到您需要的类：

A more complex solution would be to create DTO objects for deserialization then map them to your desired classes:

public class NamedSoilStat : SoilStat
{
    public string name { get; set; }
}

public class RootObject
{
    public RootObject() { this.Seed = new List<NamedSoilStat>(); }
    public List<NamedSoilStat> Seed { get; set; }
}

然后：

        var root = JsonConvert.DeserializeObject<RootObject>(txt);
        var _soilList = root.Seed.ToDictionary(t => t.name, t => new SoilStat { cost = t.cost, growthRate = t.growthRate });

至于哪个更高效，您需要自己测试。

As to which is more performant, you would need to test for yourself.

$ c> txt JSON字符串来自一个文件，并且很大，你应该考虑将它流化，而不是将其读入一个中间字符串。请参阅性能提示：优化内存使用。

Incidentally, if your txt JSON string is coming from a file, and is large, you should consider streaming it in rather than reading it into an intermediate string. See Performance Tips: Optimize Memory Usage.

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