是安全bool成语在C ++ 11过时吗? [英] Is the safe-bool idiom obsolete in C++11?
问题描述
@R的此回答。 Martinho Fernandes 表明,安全bool成语在C ++ 11中已被弃用,因为它可以被一个简单的
替换。 explicit operator bool()const;
根据标准报价在回答§4[conv] / code>:
表达式e可以隐式转换为 T
如果且仅当声明 T t = e;
形式良好时,对于一些发明的临时变量 t
(§8.5)。某些语言结构要求将表达式转换为布尔值。在这种上下文中出现的表达式 e
被称为上下文转换为 bool
如果且仅当声明 bool t(e);
形式良好,对于一些发明的临时变量t )。
突出显示的部分清楚地显示了隐式显式转换(在标准中称为上下文转换)为@R。
$ b b
-
if
, while
, code>(§6.4[stmt.select] p4
)
- 二进制逻辑运算符
& &
和 ||
(§5.14[expr.log.and / or] p1
for each)
- 逻辑否定运算符
!
(§5.3.1[expr.unary.op ] p9
)
- 条件运算符
?:
(§5.14[expr。 cond] p1
)
-
static_assert
(§7[dcl.dcl] p4 )
-
noexcept
(§15.4[except.spec] / code>)
标题中的假设是否正确?我希望我们没有忽略任何潜在的缺点。
解决方案是的。这是 示例,仅限于具有隐式用户定义转换的问题,而显式用户定义的转换运算符实际上因为这个问题而发生的事件,并用更清晰,更合乎逻辑的东西替换所有的safe-bool东西。
This answer of @R. Martinho Fernandes shows, that the safe-bool idiom is apperently deprecated in C++11, as it can be replaced by a simple
explicit operator bool() const;
according to the standard quote in the answer §4 [conv] p3
:
An expression e can be implicitly converted to a type T
if and only if the declaration T t=e;
is well-formed, for some invented temporary variable t
(§8.5). Certain language constructs require that an expression be converted to a Boolean value. An expression e
appearing in such a context is said to be contextually converted to bool
and is well-formed if and only if the declaration bool t(e);
is well-formed, for some invented temporary variable t (§8.5).
The highlighted part clearly shows the "implicit explicit cast" (called "contextual conversion" in the standard) as @R. Martinho put it.
The "certain language constructs" that require that "implicit explicit cast" seem to be the following:
if
, while
, for
(§6.4 [stmt.select] p4
)
- binary logical operators
&&
and ||
(§5.14 [expr.log.and/or] p1
for both)
- the logical negation operator
!
(§5.3.1 [expr.unary.op] p9
)
- conditional operator
?:
(§5.14 [expr.cond] p1
)
static_assert
(§7 [dcl.dcl] p4
)
noexcept
(§15.4 [except.spec] p2
)
Is our assumption in the title correct? I hope we didn't overlook any potential drawbacks.
解决方案 Yes. This is the example for problems with only having implicit user-defined conversions and explicit user-defined conversion operators were practically invented because of this problem and to replace all the safe-bool stuff with something a lot cleaner and more logical.
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