如何在switch语句中选择一个值范围? [英] How do I select a range of values in a switch statement?

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问题描述

当我尝试编译我得到这个错误:

 
1> ------构建开始:项目:配置:调试Win32 ------
1> exercise.cpp
1> c:\users\robin\documents\visual studio 2010 \projects\snake\snake \exercise.cpp(13):错误C2059:语法错误:'> ='
1> c:\users\robin\documents\visual studio 2010 \projects\snake\snake \exercise.cpp(16):错误C2059:语法错误:'> ='
1> c:\users\robin\documents\visual studio 2010 \projects\snake\snake \exercise.cpp(19):错误C2059:语法错误:'> ='
1> c:\users\robin\documents\visual studio 2010 \projects\snake\snake \exercise.cpp(22):错误C2059:语法错误:'> ='
1> c:\users\robin\documents\visual studio 2010 \projects\snake\snake \exercise.cpp(25):错误C2059:语法错误:'>'
1> c:\users\robin\documents\visual studio 2010 \projects\snake\snake\\ \\exercise.cpp(28):错误C2059:语法错误:'=='
1> c:\users\robin\documents\visual studio 2010 \projects\snake\snake\\ \\exercise.cpp(34):warning C4065:switch语句包含'default'但没有'case'标签
========== Build:0成功,1失败,0 up- date,0 skipped ==========

代码:

  #include< iostream> 
using namespace std;

int main(){
int score;

// Vraag de score
cout< 得分了:;
cin>>得分了;

//切换
切换(分数){
case> = 100:
cout< 一个;
break;
case> = 50:
cout<< b;
break;
case> = 25:
cout<< C;
break;
case> = 10:
cout<< d;
break;
case> 0:
cout<< e;
break;
case == 0:
cout<< F;
break;
default:
cout<< BAD VALUE;
break;
}
cout<< endl;
return 0;
}

如何解决这个问题?它是一个控制台应用程序,Win32和我的IDE是Windows企业C ++ 2010。



我正在从开始C ++通过游戏编程在C ++ case标签是常量表达式,而不是一般的表达式。 你需要一个if-then-else语句链来做你想做的事情。



或者,你可以枚举交换机中的值。这个运行速度稍快(虽然在像你的情况下没有关系),但是它的可读性要差得多:

  switch ){
case 0:cout<< F;打破;
case 1:
case 2:
case 3:
case 4:
case 5:
case 6:
case 7:
情况8:
情况9:
情况10:cout< e;打破;
case 11:
case 12:
case 13:
case 14:
case 15:
case 16:
case 17:
case 18:
case 19:
case 20:
case 21:
case 22:
case 23:
case 24:
case 25:cout<< C;打破;
// ...等等,你得到的想法...

}


When I try to compile I get this error:

1>------ Build started: Project: snake, Configuration: Debug Win32 ------
1>  exercise.cpp
1>c:\users\robin\documents\visual studio 2010\projects\snake\snake\exercise.cpp(13): error C2059: syntax error : '>='
1>c:\users\robin\documents\visual studio 2010\projects\snake\snake\exercise.cpp(16): error C2059: syntax error : '>='
1>c:\users\robin\documents\visual studio 2010\projects\snake\snake\exercise.cpp(19): error C2059: syntax error : '>='
1>c:\users\robin\documents\visual studio 2010\projects\snake\snake\exercise.cpp(22): error C2059: syntax error : '>='
1>c:\users\robin\documents\visual studio 2010\projects\snake\snake\exercise.cpp(25): error C2059: syntax error : '>'
1>c:\users\robin\documents\visual studio 2010\projects\snake\snake\exercise.cpp(28): error C2059: syntax error : '=='
1>c:\users\robin\documents\visual studio 2010\projects\snake\snake\exercise.cpp(34): warning C4065: switch statement contains 'default' but no 'case' labels
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========

Code:

#include <iostream>
using namespace std;

int main(){
    int score;

    //Vraag de score
    cout << "Score:";
    cin >> score;

    //Switch
    switch(score){
        case >= 100:
            cout << "a";
            break;
        case >= 50:
            cout << "b";
            break;
        case >= 25:
            cout << "c";
            break;
        case >= 10:
            cout << "d";
            break;
        case > 0:
            cout << "e";
            break;
        case == 0:
            cout << "f";
            break;
        default:
            cout << "BAD VALUE";
            break;
    }
    cout << endl;
    return 0;
}

How can I fix this problem? It's a console application, Win32 and my IDE is Windows Enterprise C++ 2010.

I'm learning from Beginning C++ Through Game Programming.

解决方案

In C++ case labels are constant expressions, not expressions in general. You need a chain of if-then-else statements to do what you are trying to do.

Alternatively, you can enumerate the values in the switch. This runs marginally faster (though it does not matter in cases like yours), but it is considerably less readable:

switch(score) {
    case 0: cout << "f"; break;
    case 1:
    case 2:
    case 3:
    case 4:
    case 5:
    case 6:
    case 7:
    case 8:
    case 9:
    case 10: cout << "e"; break;
    case 11:
    case 12:
    case 13:
    case 14:
    case 15:
    case 16:
    case 17:
    case 18:
    case 19:
    case 20:
    case 21:
    case 22:
    case 23:
    case 24:
    case 25: cout << "c"; break;
    // ...and so on, you get the idea...

}

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