在C ++中使用getline（） [英] Using getline() in C++

问题描述

我有一个问题使用getline方法来获取一个消息，用户类型，我使用像：

I have a problem using getline method to get a message that user types, I'm using something like:

string messageVar;
cout << "Type your message: ";
getline(cin, messageVar);

但是，它不是停止获取输出值，这有什么问题？

However, it's not stopping to get the output value, what's wrong with this?

推荐答案

如果你在 cin>> something ，您需要从中间的缓冲区中刷新换行符。您可以使用 cin.ignore（）

If you're using getline after cin >> something, you need to flush the newline character out of the buffer in between. You can do it by using cin.ignore()

这样做：

string messageVar;
cout << "Type your message: ";
cin.ignore(); 
getline(cin, messageVar);

这是因为>> 操作符在输入缓冲区中留下换行符 \\\
。这可能会成为一个问题，当你做无格式的输入，如 getline（），读取输入直到找到换行符。这会发生，它会立即停止读取，因为 \\\
在你以前的操作中被挂在那里。

This happens because the >> operator leaves a newline \n character in the input buffer. This may become a problem when you do unformatted input, like getline(), which reads input until a newline character is found. This happening, it will stop reading immediatly, because of that \n that was left hanging there in your previous operation.

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