获取当前光标位置 [英] Get current cursor position

问题描述

我想获取窗口的当前鼠标位置，并将其分配给2个变量 x 和 y （相对于窗口的坐标，而不是整个屏幕）。

I want to get the current mouse position of the window, and assign it to 2 variables x and y (co-ordinates relative to the window, not to the screen as a whole).

我使用Win32和C ++。

I'm using Win32 and C++.

还有一个快速的奖励问题：你如何隐藏光标/取消隐藏光标？

And a quick bonus question: how would you go about hiding the cursor/unhiding it?

推荐答案

通过调用 GetCursorPos 。

POINT p;
if (GetCursorPos(&p))
{
    //cursor position now in p.x and p.y
}

这将返回相对于屏幕坐标的光标位置。致电 ScreenToClient 以映射到窗口坐标。

This returns the cursor position relative to screen coordinates. Call ScreenToClient to map to window coordinates.

if (ScreenToClient(hwnd, &p))
{
    //p.x and p.y are now relative to hwnd's client area
}

---

您可以使用 ShowCursor 。

ShowCursor(FALSE);//hides the cursor
ShowCursor(TRUE);//shows it again

调用隐藏光标时再次显示的光标。

You must ensure that every call to hide the cursor is matched by one that shows it again.

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