当你在C ++中释放一个指针两次或更多时会发生什么？ [英] What happens when you deallocate a pointer twice or more in C++?

问题描述

int main(){
Employee *e = new Employee();

delete e;
delete e;
...
delete e;
return 0;

}

推荐答案

e '不是引用，它是一个指针。如果您通过指针多次尝试删除一个对象，则会得到未定义的行为。

e's not a reference, it's a pointer. You get undefined behaviour if you try to delete an object through a pointer more that once.

这意味着，从出现工作到崩溃或完全随机的事情都会发生。

This means that pretty much anything can happen from 'appearing to work' to 'crashing' or something completely random.

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