如何测试字符串的字符串 [英] how to test a string for letters only
本文介绍了如何测试字符串的字符串的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
字符串名称;
cout<< 输入您的姓名
cin>>名称;
string letters =qwertyuiopasdfghjklzxcvbnm;
string :: iterator it;
for(it = name.begin(); it = name.end(); it ++)
{
size_t found = letters.find(it);
}
解决方案
STL方式:
struct TestFunctor
{
bool stringIsCorrect;
TestFunctor()
:stringIsCorrect(true)
{}
void operator()(char ch)
{
if(stringIsCorrect & ch(< ='z'& ch> ='a')||(ch <='Z'& ch> ='A'
stringIsCorrect = false;
}
}
TestFunctor functor;
for_each(name.begin(),name.end(),functor);
if(functor.stringIsCorrect)
cout<< 好极了;
how could I test a string against only valid characters like letters a-z?...
string name;
cout << "Enter your name"
cin >> name;
string letters = "qwertyuiopasdfghjklzxcvbnm";
string::iterator it;
for(it = name.begin(); it = name.end(); it++)
{
size_t found = letters.find(it);
}
解决方案
STL way:
struct TestFunctor
{
bool stringIsCorrect;
TestFunctor()
:stringIsCorrect(true)
{}
void operator() (char ch)
{
if(stringIsCorrect && !((ch <= 'z' && ch >= 'a') || (ch <= 'Z' && ch >= 'A')))
stringIsCorrect = false;
}
}
TestFunctor functor;
for_each(name.begin(), name.end(), functor);
if(functor.stringIsCorrect)
cout << "Yay";
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