c ++传递一个const对象引用到一个函数 [英] c++ passing a const object reference to a function

问题描述

错误：传递'const QByteArray'作为'this'参数的'QByteArray& QByteArray :: append（const QByteArray&）'舍弃限定符[-fpermissive]

error: passing 'const QByteArray' as 'this' argument of 'QByteArray& QByteArray::append(const QByteArray&)' discards qualifiers [-fpermissive]

作为函数参数我做到了。
，但现在我得到一个错误!!，
i dnt想让函数常量，因为我必须转换qbyte数组中的数据为短，然后附加另一个数组。

since it is a convention to make objects const while passing as function arguments i have done it. but now i am getting an error!!, i dnt want to make the function constant as i have to convert data in qbyte array into short and then append it another array.

QByteArray ba((const char*)m_output.data(), sizeof(ushort));
    playbackBuffer.append(ba);

我真的需要将这个数组传递给 playbackbuffer ;

这是给我在 playbackBuffer.append（ba）;

I really need to pass this array into playbackbuffer;
It is giving me an error on playbackBuffer.append(ba);

请帮助

提前感谢

please help
thanks in advance

推荐答案

这意味着你正在调用一个非const成员函数一个const成员。假设您的 append 函数修改了字节数组。有了const引用，你不应该修改。

This means you are calling a non-const member function on a const member. Presumably, your append function modifies the byte array. With a const reference, you shouldn't be modifying.

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