铸造矢量< T>到向量< const T> [英] Cast vector<T> to vector<const T>
问题描述
我有一个类型的向量< T>的成员变量
(其中T是一个自定义类,但也可以是int)
有一个函数,我想要从这个向量返回一个指针,但我不想让调用者能够改变向量或它的项目。所以我想要的返回类型是 const向量< const T> *
I have a member variable of type vector<T>
(where is T is a custom class, but it could be int as well.)
I have a function from which I want to return a pointer to this vector, but I don't want the caller to be able to change the vector or it's items. So I want the return type to be const vector<const T>*
工作。编译器不断地抱怨T与const T不兼容。
None of the casting methods I tried worked. The compiler keeps complaining that T is not compatible with const T.
这里有一些代码演示了我想要做的事情;
Here's some code that demonstrates the gist of what I'm trying to do;
vector<int> a;
const vector<const int>* b = (const vector<const int>* ) (&a);
此代码不为我编译。
提前感谢!
推荐答案
如果你有一个 const向量< int>
您不能修改容器,也不能修改容器中的任何元素。你不需要一个 const向量< const int>
来实现这些语义。
If you have a const vector<int>
you cannot modify the container, nor can you modify any of the elements in the container. You don't need a const vector<const int>
to achieve those semantics.
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