最简单的方法使用OpenCV旋转90度图像？ [英] Easiest way to rotate by 90 degrees an image using OpenCV?

问题描述

什么是旋转IplImage / cv :: Mat 90度的最好的方法（在c / c ++中）？我假设必须有一些东西比使用矩阵转换更好，但我似乎找不到除了在API和在线之外的任何东西。

解决方案

换位更新：

您应该使用 cvTranspose c $ c>或 cv :: transpose（）因为（正确地指出）它更有效率。再次，我建议升级到OpenCV2.0，因为大多数 cvXXX 函数只是将 IplImage * 结构转换为 Mat 对象（无深拷贝）。如果将图像存储在 Mat 对象中， Mat.t（）将返回转置。



任何轮换：

您应该使用cvWarpAffine定义一般框架中的旋转矩阵变换矩阵。我强烈建议您升级到 OpenCV2.0 ，它有几个功能以及 Mat 封装了矩阵和图像的类。使用2.0，您可以使用 warpAffine 访问上述内容。

What is the best way (in c/c++) to rotate an IplImage/cv::Mat by 90 degrees? I would assume that there must be something better than transforming it using a matrix, but I can't seem to find anything other than that in the API and online.

解决方案

Update for transposition:

You should use cvTranspose() or cv::transpose() because (as you rightly pointed out) it's more efficient. Again, I recommend upgrading to OpenCV2.0 since most of the cvXXX functions just convert IplImage* structures to Mat objects (no deep copies). If you stored the image in a Mat object, Mat.t() would return the transpose.

Any rotation:

You should use cvWarpAffine by defining the rotation matrix in the general framework of the transformation matrix. I would highly recommend upgrading to OpenCV2.0 which has several features as well as a Mat class which encapsulates matrices and images. With 2.0 you can use warpAffine to the above.

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