我如何获得网页的内容 [英] How can i get content of web-page
问题描述
我试图获取网页数据的字符串,而不是我可以解析它。我没有发现任何方法在qwebview,qurl和另一个。你可以帮帮我吗? Linux,C ++,Qt。
i'm trying to get web-page data in string that than i could parse it. I didn't found any methods in qwebview, qurl and another. Could you help me? Linux, C++, Qt.
编辑:
感谢您的帮助。代码是工作,但下载后的一些页面已破坏字符集。
我尝试这样修复它:
Thanks for help. Code is working, but some pages after downloading have broken charset. I tried something like this to repair it:
QNetworkRequest *request = new QNetworkRequest(QUrl("http://ru.wiktionary.org/wiki/bovo"));
request->setRawHeader( "User-Agent", "Mozilla/5.0 (X11; U; Linux i686 (x86_64); "
"en-US; rv:1.9.0.1) Gecko/2008070206 Firefox/3.0.1" );
request->setRawHeader( "Accept-Charset", "win1251,utf-8;q=0.7,*;q=0.7" );
request->setRawHeader( "charset", "utf-8" );
request->setRawHeader( "Connection", "keep-alive" );
manager->get(*request);
任何结果=(。
推荐答案
您看过了 QNetworkAccessManager 吗?这里有一个粗略的和准备好的示例用法:
Have you looked at QNetworkAccessManager? Here's a rough and ready sample illustrating usage:
class MyClass : public QObject
{
Q_OBJECT
public:
MyClass();
void fetch();
public slots:
void replyFinished(QNetworkReply*);
private:
QNetworkAccessManager* m_manager;
};
MyClass::MyClass()
{
m_manager = new QNetworkAccessManager(this);
connect(m_manager, SIGNAL(finished(QNetworkReply*)),
this, SLOT(replyFinished(QNetworkReply*)));
}
void MyClass::fetch()
{
m_manager->get(QNetworkRequest(QUrl("http://stackoverflow.com")));
}
void MyClass::replyFinished(QNetworkReply* pReply)
{
QByteArray data=pReply->readAll();
QString str(data);
//process str any way you like!
}
在完成信号,您将通过一个 QNetworkReply 对象,您可以从它继承的 QIODevice 。执行此操作的一种简单方法是调用 readAll 获取 QByteArray 。您可以从该QByteArray构建一个 QString ,并执行任何您想要做的操作
In your in your handler for the finished signal you will be passed a QNetworkReply object, which you can read the response from as it inherits from QIODevice. A simple way to do this is just call readAll to get a QByteArray. You can construct a QString from that QByteArray and do whatever you want to do with it.
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