如何使用C ++中的计时器在给定时间内强制输入? [英] How to use a timer in C++ to force input within a given time?
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问题描述
我想在C ++中实现超时功能。
I want to implement a time out feature in C++.
如果用户在2秒内未输入值,则程序必须显示超时语句并再次询问输入
If the user does not input the value within 2 seconds then the program must display the time-out statement and ask the input again
EX(OUTPUT SCREEN):
EX(OUTPUT SCREEN):
Timer=0;
Please enter the input: //if input is not given within 2 seconds then
Time-out: 2 seconds
Timer again set to 0
Please enter the input: //if input is not given within 2 seconds then
Time-out: 2 seconds
Timer again set to 0
Please enter the input:22
Data accepted
Terminate the program`
代码:
#include<iostream>
#include<time.h>
using namespace std;
int main()
{
clock_t endwait;
endwait = 2000 ;
cout<<endwait;
while (clock() < endwait)
{
cout<<"Please enter the input:";
}
return 0;
}
我已经研究了上面的代码。但这只发生在进入WHILE循环时。
I have worked on the above code. But this happens only while entering the WHILE loop. How shall i do it in a way so that, I get the required output.
推荐答案
#include <iostream>
#include <thread>
#include <chrono>
#include <mutex>
#include <condition_variable>
using namespace std;
condition_variable cv;
int value;
void read_value() {
cin >> value;
cv.notify_one();
}
int main()
{
cout << "Please enter the input: ";
thread th(read_value);
mutex mtx;
unique_lock<mutex> lck(mtx);
while (cv.wait_for(lck, chrono::seconds(2)) == cv_status::timeout)
{
cout << "\nTime-Out: 2 second:";
cout << "\nPlease enter the input:";
}
cout << "You entered: " << value << '\n';
th.join();
return 0;
}
输出:
Please enter the input:
Time-Out: 2 second:
Please enter the input:
Time-Out: 2 second:
Please enter the input:22
You entered: 22
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