如何在C ++中将一个int附加到字符串中？ [英] How do you append an int to a string in C++?

问题描述

int i = 4;
string text = "Player ";
cout << (text + i);

我想打印 Player 4 。

上面显然是错误的，但它显示了我在这里要做的事。是否有一个简单的方法来做到这一点，或者我必须开始添加新的包括？

The above is obviously wrong but it shows what I'm trying to do here. Is there an easy way to do this or do I have to start adding new includes?

推荐答案

可以直接写入整数，如

std::cout << text << i;

将各种对象转换为字符串的C ++方法是通过串流。如果你没有一个方便，只需创建一个。

The C++ way of converting all kinds of objects to strings is through string streams. If you don't have one handy, just create one.

#include <sstream>

std::ostringstream oss;
oss << text << i;
std::cout << oss.str();

或者，您只需转换整数并将其追加到字符串即可。

Alternatively, you can just convert the integer and append it to the string.

oss << i;
text += oss.str();

最后，Boost库提供 boost :: lexical_cast ， in type cast。

Finally, the Boost libraries provide boost::lexical_cast, which wraps around the stringstream conversion with a syntax like the built-in type casts.

#include <boost/lexical_cast.hpp>

text += boost::lexical_cast<std::string>(i);

这也可以反过来，也就是解析字符串。

This also works the other way around, i.e. to parse strings.

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