C ++ - 为什么静态成员函数不能用'const'限定符创建 [英] C++ - Why static member function can't be created with 'const' qualifier

问题描述

今天我有一个问题。我在需要一个静态成员函数，const不是必须的，但更好。但是，我没有成功我的努力。 c>

当你应用 const 限定符到非静态成员函数，它会影响 this 指针。对于 C 类的const限定成员函数，此指针的类型为 C const * ，而对于不是const限定的成员函数， this 指针的类型为 C * / code>。

静态成员函数没有 this 指针不是在类的特定实例上调用），因此静态成员函数的const限定没有任何意义。

Today I got a problem. I am in the need of a static member function, const is not a must but a better. But, I didn't succeed in my efforts. Can anybody say why or how?

解决方案

When you apply the const qualifier to a nonstatic member function, it affects the this pointer. For a const-qualified member function of class C, the this pointer is of type C const*, whereas for a member function that is not const-qualified, the this pointer is of type C*.

A static member function does not have a this pointer (such a function is not called on a particular instance of a class), so const qualification of a static member function doesn't make any sense.

这篇关于C ++ - 为什么静态成员函数不能用'const'限定符创建的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！