为类重载运算符new [英] Overloading operator new for a class

问题描述

当我们重载一个类的新运算符时，我们将该函数声明为一个成员函数。
例如：

When we overload new operator of a class, we declare the function as a member function. For eg:

class OpNew {
public:
    OpNew() { cout << "OpNew::OpNew()" << endl;}
    void* operator new(size_t sz) {
         cout << "OpNew::new: "
            << sz << " bytes" << endl;
         return ::new char[sz];
    }
};

语句 OpNew * obj = new OpNew 在发动机罩下工作？因为重载的新是OpNew类的成员而不是静态的。那么编译器如何保证这个调用 new 成功函数成功？

How does the statement OpNew *obj = new OpNew work under the hood ? as overloaded new is a member of OpNew class not a static. So how does compiler ensure this call to new member function succeeds?

推荐答案

运算符new（）或 ]

An operator new() or operator new[]() for a class is always a static class member, even if it is not declared with the keyword static.

类 T 的任何分配函数都是静态成员（即使没有显式声明 static ）。 / p>

Any allocation function for a class T is a static member (even if not explicitly declared static).

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