为什么没有std :: stou？ [英] Why is there no std::stou?

问题描述

C ++ 11添加了一些新的字符串转换函数：

C++11 added some new string conversion functions:

http://en.cppreference.com/w/cpp/string/basic_string/stoul

它包括stoi（string to int ），stol（string to long），stoll（string to long long），stoul（string to unsigned long），stoull（string to unsigned long long）。值得注意的是它的缺乏是一个stou（字符串到无符号）函数。是否有某种原因不需要它，但所有其他的都是？

It includes stoi (string to int), stol (string to long), stoll (string to long long), stoul (string to unsigned long), stoull (string to unsigned long long). Notable in its absence is a stou (string to unsigned) function. Is there some reason it is not needed but all of the others are?

相关：否sto {short，unsigned short}。函数在C ++ 11？

推荐答案

最好的答案是C库没有相应的 ; strtou &，并且C ++ 11字符串函数都是围绕C库函数的非常隐蔽的包装： std :: sto * 函数镜像 strto * 和 std :: to_string 函数使用 sprintf 。

The most pat answer would be that the C library has no corresponding “strtou”, and the C++11 string functions are all just thinly veiled wrappers around the C library functions: The std::sto* functions mirror strto*, and the std::to_string functions use sprintf.

编辑：KennyTM指出， stoi 和 stol 使用 strtol 作为底层转换函数，但它仍然是神秘的为什么存在使用 strtoul 的 stoul ，没有相应的 stou 。

As KennyTM points out, both stoi and stol use strtol as the underlying conversion function, but it is still mysterious why while there exists stoul that uses strtoul, there is no corresponding stou.

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