是否可以使用C型铸造内置类型？ [英] Is it OK to use C-style cast for built-in types?

问题描述

在这里阅读了很多关于C风格铸造在C ++中的答案我还有一个小问题。我可以对内置类型如 long x =（long）y; 使用C风格的转换，还是认为它是坏的和危险的？

After reading here a lot of answers about C-style casting in C++ I still have one little question. Can I use C-style casting for built-in types like long x=(long)y; or it's still considered bad and dangerous?

推荐答案

我不会，原因如下：

• 丑陋，应该是丑陋的，并在代码中脱颖而出，并且可以使用grep和类似工具查找。


• 始终使用C ++转换是一个更容易记住的简单规则


• C ++风格的转换为其他开发人员提供了更多的信息


• C风格的Cast可能会允许您执行不需要的转换 - 如果您有一个接口（int *），而您正在使用c风格的转型传递一个const int *，并且界面改变为接受一个长*，你的代码使用c风格的casts将继续工作，即使它不是你想要的。

• Casts are ugly and should be ugly and stand out in your code, and be findable using grep and similar tools.
• "Always use C++ casts" is a simple rule that is much more likely to be remembered and followed than, "Use C++ casts on user-defined types, but it's OK to use C-style casts on built-in types."
• C++ style casts provide more information to other developers about why the cast is necessary.
• C-style casts may let you do conversions you didn't intend -- if you have an interface that takes in (int*) and you were using c-style casts to pass it a const int*, and the interface changes to take in a long*, your code using c-style casts will continue to work, even if it's not what you wanted.

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