什么是跨平台的方式来获取当前目录? [英] What is a cross-platform way to get the current directory?
问题描述
我需要一个跨平台的方式来获取当前的工作目录(是的,getcwd做我想要的)。我认为这可能会诀窍:
I need a cross-platform way to get the current working directory (yes, getcwd does what I want). I thought this might do the trick:
#ifdef _WIN32
#include <direct.h>
#define getcwd _getcwd // stupid MSFT "deprecation" warning
#elif
#include <unistd.h>
#endif
#include <string>
#include <iostream>
using namespace std;
int main()
{
string s_cwd(getcwd(NULL,0));
cout << "CWD is: " << s_cwd << endl;
}
我读到:
_getcwd
at MSDNgetcwd
at Kernel.orggetcwd
at Apple.com
应该没有内存泄漏,它也应该在Mac上正常工作?
There should be no memory leaks, and it should work on a Mac as well, correct?
更新:我恐怕在这里仍然是错误的(我试图避免创建一个确定的长度的字符数组,因为没有正确的方法来获得一个体面的长度getcwd):
UPDATE: I fear something is still wrong here (I'm trying to avoid creating a char array with a determined length, as there's no proper way to get a decent length for getcwd):
char* a_cwd = getcwd(NULL,0);
string s_cwd(a_cwd);
free(a_cwd); // or delete a_cwd?
推荐答案
您不能调用 getcwd
使用NULL缓冲区。根据 Opengroup :
You cannot call getcwd
with a NULL buffer. As per the Opengroup:
如果buf是一个空指针,则getcwd()的行为是未指定的。
If buf is a null pointer, the behavior of getcwd() is unspecified.
返回NULL可以打破字符串构造函数。
Also, getcwd can return NULL which can break a string constructor.
您需要将其更改为:
char buffer[SIZE];
char *answer = getcwd(buffer, sizeof(buffer));
string s_cwd;
if (answer)
{
s_cwd = answer;
}
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