将未知大小的std ::数组传递给函数 [英] Passing a std::array of unknown size to a function

问题描述

在C ++ 11中，我将如何编写一个函数（或方法），该函数采用已知类型但未知大小的std ::数组？

In C++11, how would I go about writing a function (or method) that takes a std::array of known type but unknown size?

// made up example
void mulArray(std::array<int, ?>& arr, const int multiplier) {
    for(auto& e : arr) {
        e *= multiplier;
    }
}

// lets imagine these being full of numbers
std::array<int, 17> arr1;
std::array<int, 6>  arr2;
std::array<int, 95> arr3;

mulArray(arr1, 3);
mulArray(arr2, 5);
mulArray(arr3, 2);

在我的搜索过程中，我只找到使用模板的建议，但是那些看起来很乱（标题中的方法定义）

During my search I only found suggestions to use templates, but those seems messy (method definitions in header) and excessive for what I'm trying to accomplish.

有没有简单的方法来使这个工作，就像一个简单的C风格的数组？

Is there a simple way to make this work, as one would with plain C-style arrays?

推荐答案

有没有简单的方法来使这个工作，就像一个简单的C风格的数组？ p>

Is there a simple way to make this work, as one would with plain C-style arrays?

否。你真的不能这样做，除非你使你的函数模板（或使用另一种类型的容器，如 std :: vector 在

No. You really cannot do that unless you make your function a function template (or use another sort of container, like an std::vector, as suggested in the comments to the question):

template<std::size_t SIZE>
void mulArray(std::array<int, SIZE>& arr, const int multiplier) {
    for(auto& e : arr) {
        e *= multiplier;
    }
}

这里是live示例 。

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