指针取消引用运算符（（*）vs - >） [英] Pointer dereference operator ( (*) vs -> )

问题描述

执行之间有一般差异

(*ptr).method()

vs

ptr->method()

我在另一个问题的评论中看到这个问题，我想在这里问。虽然我只是记得几乎每个操作符在C ++可以重载，所以我想答案将取决于。

I saw this question in a comment on another question and thought I would ask it here. Although I just remembered that pretty much every operator in C++ can be overloaded, so I guess the answer will depend. But in general, is there a difference between doing one versus the other?

推荐答案

由于jamesdlin已经提到， * 和 - > 运算符可以重载类类型。

As "jamesdlin" already noted, the * and -> operators can be overloaded for class types.

然后两个表达式（* ptr）.method（）和 ptr-> gt（）具有不同的效果。

And then the two expressions (*ptr).method() and ptr->method() can have different effect.

但是，对于内建的运算符，两个表达式是等价的。

However, for the built-in operators the two expressions are equivalent.

当你跟踪一系列指针时， - > 运算符更方便，因为。

The -> operator is more convenient when you're following a chain of pointers, because . has higher precedence than *, thus requiring a lot of ungrokkable parentheses.

请考虑：

pBook->author->snailMail->zip

与

(*(*(*pBook).author).snailMail).zip

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