用什么替换巨型switch语句？ [英] Replace giant switch statement with what?
问题描述
我有一个代码来解析一些模板文件，当它找到一个占位符，它用一个值替换它。像：
I have a code that parses some template files and when it finds a placeholder, it replaces it with a value. Something like:
<html>
<head>
<title>%title%</title>
</head>
<body bgcolor="%color%">
...etc.
在代码中，解析器找到那些，调用这个函数：
In code, the parser finds those, calls this function:
string getContent(const string& name)
{
if (name == "title")
return page->getTitle();
else if (name == "color")
return getBodyColor();
...etc.
}
，然后将原始占位符替换为返回值。
and then replaces the original placeholder with returned value.
在实际情况下，它不是一个虚拟网页，并且有许多（50+）不同的占位符可以发生。
In real case, it is not a dummy web page, and there are many (50+) different placeholders that can occur.
我的代码是C ++，但我想这个问题存在于任何语言。这是更多关于算法和OO设计我猜。只有重要的是，这必须编译，即使我想我不能有任何动态/ eval'd代码。
My code is C++, but I guess this problem exists with any language. It's more about algorithms and OO design I guess. Only important thing is that this must be compiled, even if I wanted I couldn't have any dynamic/eval'd code.
我虽然关于实现责任模式，但它似乎不会改善的情况。
I though about implementing Chain of Responsibility pattern, but it doesn't seem it would improve the situation much.
更新：我也关注此评论。
推荐答案
使用将标记名称映射到标记处理程序的字典。
Use a dictionary that maps tag names to a tag handler.
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