你如何在c ++中模拟使用RAII的类 [英] How do you mock classes that use RAII in c++

问题描述

这是我的问题，我想嘲笑一个类，在初始化时创建一个线程，并在销毁时关闭它。没有理由让我的mock类实际创建和关闭线程。但是，为了模仿一个类，我继承了它。当我创建一个我的mock类的新实例，基类构造函数被调用，创建线程。当我的mock对象被销毁时，基类析构函数被调用，试图关闭线程。

Here's my issue, I'd like to mock a class that creates a thread at initialization and closes it at destruction. There's no reason for my mock class to actually create and close threads. But, to mock a class, I have inherit from it. When I create a new instance of my mock class, the base classes constructor is called, creating the thread. When my mock object is destroyed, the base classes destructor is called, attempting to close the thread.

如何嘲笑RAII类而不必处理实际资源？

How does one mock an RAII class without having to deal with the actual resource?

推荐答案

你可以创建一个描述类型的接口，并且同时拥有真正的类和mock类。所以如果你有：

You instead make an interface that describes the type, and have both the real class and the mock class inherit from that. So if you had:

class RAIIClass {
 public:
  RAIIClass(Foo* f);
  ~RAIIClass();
  bool DoOperation();

 private:
  ...
};

您将创建一个界面：

class MockableInterface {
 public:
  MockableInterface(Foo* f);
  virtual ~MockableInterface();
  virtual bool DoOperation() = 0;
};

然后从那里开始。

这篇关于你如何在c ++中模拟使用RAII的类的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！