std ::索引和插入调用之间的映射差异 [英] std::map difference between index and insert calls
问题描述
索引重载运算符和std :: map的insert方法调用之间的区别是什么?
ie:
some_map [x] = 500;
vs。
code> some_map.insert(pair< std :: string,int>(x,500));
我相信insert()不会覆盖现有值,并且可以通过测试所返回的迭代器/对值中的bool值来检查操作的结果
对下标运算符[]的赋值仅覆盖其中的任何值插入一个条目,如果没有已经有一个条目)
插入和[]操作符可能会导致问题,如果你没有期望的行为,
std :: 地图< int,std :: string *> intMap;
std :: string * s1 = new std :: string;
std :: string * s2 = new std :: string;
intMap.insert(std :: make_pair(100,s1)); // inserted
intMap.insert(std :: make_pair(100,s2)); //失败,s2不在map中,如果不整理就可能泄漏
std :: map< int,std :: string *> intMap;
std :: string * s1 = new std :: string;
std :: string * s2 = new std :: string;
intMap [100] = s1; // inserted
intMap [100] = s2; // inserted,s1现在从地图上删除,如果不整理就可能泄漏
,但尚未编译它们,因此可能会出现语法错误
What is the difference between the index overloaded operator and the insert method call for std::map?
ie:
some_map["x"] = 500;
vs.
some_map.insert(pair<std::string, int>("x", 500));
I believe insert() will not overwrite an existing value, and the result of the operation can be checked by testing the bool value in the iterator/pair value returned
The assignment to the subscript operator [] just overwrites whatever's there (inserting an entry if there isn't one there already)
Either of the insert and [] operators can cause issues if you're not expecting that behaviour and don't accommodate for it.
Eg with insert:
std::map< int, std::string* > intMap;
std::string* s1 = new std::string;
std::string* s2 = new std::string;
intMap.insert( std::make_pair( 100, s1 ) ); // inserted
intMap.insert( std::make_pair( 100, s2 ) ); // fails, s2 not in map, could leak if not tidied up
and with [] operator:
std::map< int, std::string* > intMap;
std::string* s1 = new std::string;
std::string* s2 = new std::string;
intMap[ 100 ] = s1; // inserted
intMap[ 100 ] = s2; // inserted, s1 now dropped from map, could leak if not tidied up
I think those are correct, but haven't compiled them, so may have syntax errors
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