延迟执行1秒 [英] Delay execution 1 second

问题描述

所以我试图编写一个简单的基于tick的游戏。我在linux机器上用C ++写。

So I am trying to program a simple tick-based game. I write in C++ on a linux machine. The code below illustrates what I'm trying to accomplish.

for (unsigned int i = 0; i < 40; ++i)
{
    functioncall();
    sleep(1000); // wait 1 second for the next function call
}

工作。它似乎是睡眠了40秒，然后打印输出的结果是从函数调用。

Well, this doesn't work. It seems that it sleeps for 40 seconds, then prints out whatever the result is from the function call.

我也尝试创建一个新的函数叫延迟，它看起来像这个：

I also tried creating a new function called delay, and it looked like this:

void delay(int seconds)
{
    time_t start, current;

    time(&start);

    do
    {
        time(&current);
    }
    while ((current - start) < seconds);
}

任何人？

推荐答案

重申其他人已经说明的具体示例：

To reiterate on what has already been stated by others with a concrete example:

假设你使用 std :: cout 输出，你应该调用 std :: cout.flush（）; 正好在sleep命令之前。请参见此MS知识库文章。

Assuming you're using std::cout for output, you should call std::cout.flush(); right before the sleep command. See this MS knowledgebase article.

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