通过引用将thrust :: device_vector传递给函数 [英] passing thrust::device_vector to a function by reference

问题描述

我试图传递 device_vector 结构

struct point 
{
    unsigned int x;
    unsigned int y;
}

以下列方式：

void print(thrust::device_vector<point> &points, unsigned int index)
{
    std::cout << points[index].y << points[index].y << std::endl;
}

myvector已正确初始化

myvector was initialized properly

print(myvector, 0);

我遇到以下错误：

error: class "thrust::device_reference<point>" has no member "x"
error: class "thrust::device_reference<point>" has no member "y"

它有什么问题？

推荐答案

不幸的是， device_reference< T> 不能公开 T ，但它可以转换为 T 。

Unfortunately, device_reference<T> cannot expose members of T, but it can convert to T.

c $ c>，将每个元素的临时副本转换为临时 temp ：

To implement print, make a temporary copy of each element by converting it to a temporary temp:

void print(thrust::device_vector<point> &points, unsigned int index)
{
    point temp = points[index];
    std::cout << temp.y << temp.y << std::endl;
}

每次调用 print ，它会导致从GPU到系统内存的传输，以创建临时的。如果您需要一次打印点的整个集合，更高效的方法将复制整个向量 points en masse to a host_vector 或 std :: vector （使用 thrust :: copy ），然后正常遍历集合。

Each time you invoke print, it causes a transfer from GPU to system memory to create the temporary. If you need to print the entire collection of points at once, a more efficient method would copy the entire vector points en masse to a host_vector or std::vector (using thrust::copy) and then iterate through the collection as normal.

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