将一个结构push_back（）一个向量 [英] push_back() a struct into a vector

问题描述

如何将一个结构push_back到一个向量？

How can I push_back a struct into a vector?

struct point {
    int x;
    int y;
};

vector <point> a;

a.push_back( ??? );

推荐答案

point mypoint = {0, 1};
a.push_back(mypoint);

或者如果允许，请给予点一个构造函数，所以你可以使用一个临时的：

Or if you're allowed, give point a constructor, so that you can use a temporary:

a.push_back(point(0,1));

有些人会对象，如果你把一个构造函数声明为 struct ，它使它非POD，也许你不能控制 point 的定义。因此，此选项可能不适用于您。但是，你可以编写一个方便的函数：

Some people will object if you put a constructor in a class declared with struct, and it makes it non-POD, and maybe you aren't in control of the definition of point. So this option might not be available to you. However, you can write a function which provides the same convenience:

point make_point(int x, int y) {
    point mypoint = {x, y};
    return mypoint;
}

a.push_back(make_point(0, 1));

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