_ITERATOR_DEBUG_LEVEL = 1是什么意思？ [英] What does _ITERATOR_DEBUG_LEVEL = 1 mean?

问题描述

在VS2010，C ++项目我得到这个错误时链接在x64 /版本：

错误LNK2038：检测到不匹配'_ITERATOR_DEBUG_LEVEL'：值'0' t匹配值'1'

所有其他配置/平台组合链接很好。因此，静态库建立与_ITERATOR_DEBUG_LEVEL设置为0和.dll，它依赖于它以某种方式已_ITERATOR_DEBUG_LEVEL设置为1.我试图找出这是什么意思，所以我可以找出如何关闭它！

在Google搜索中发现的对此错误的唯一引用是_ITERATOR_DEBUG_LEVEL与值0和2冲突。这表示尝试将发行版与调试版链接。但我相信这不是这里的情况。

解决方案

挣扎一小时后，我想出了这个问题，

  _ITERATOR_DEBUG_LEVEL = 0（在发布模式下）
 _ITERATOR_DEBUG_LEVEL = 1（如果定义了_SECURE_SCL， $ b _ITERATOR_DEBUG_LEVEL = 2（在调试模式下）
  

不知何故，我将_SECURE_SCL定义为预处理器定义我的DLL的Release / x64配置，我不得不眯着眼睛真的很难注意到它。一旦我删除了该定义，错误就消失了。

编辑：我发现这个关于msdn的漂亮讲座/教程说明_ITERATOR_DEBUG_LEVEL 。不幸的是，它需要一个相当新版本的Microsoft Silverlight来观看。

In VS2010, C++ project I get this error when linking in x64/Release:

error LNK2038: mismatch detected for '_ITERATOR_DEBUG_LEVEL': value '0' doesn't match value '1'

All other configuration/platform combinations link just fine. So a static library is built with _ITERATOR_DEBUG_LEVEL set to 0 and the .dll that depends on it somehow has _ITERATOR_DEBUG_LEVEL set to 1. I'm trying to figure out what that means so I can figure out how to turn it off!

The only references to this error that I found while Googling are when _ITERATOR_DEBUG_LEVEL's conflict with values of 0 and 2. That indicates an attempt to link release with debug. But I'm sure that's not the case here.

解决方案

Well, after struggling with this for an hour I figured it out right after I asked the question... for posterity:

_ITERATOR_DEBUG_LEVEL = 0 (in release mode)
_ITERATOR_DEBUG_LEVEL = 1 (in release mode if _SECURE_SCL is defined)
_ITERATOR_DEBUG_LEVEL = 2 (in debug mode)

Somehow I had _SECURE_SCL defined as a preprocessor definition only in the Release/x64 configuration of my DLL and I had to squint really hard to notice it. Once I removed that definition, the error went away.

Edit: I found this nice lecture/tutorial on msdn that (among other things) explains _ITERATOR_DEBUG_LEVEL. Unfortunately, it does require a fairly recent version of Microsoft Silverlight to watch.

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