你真的有一个函数/方法没有一个身体,但只是一个try / catch块? [英] Can you really have a function/method without a body but just a try/catch block?
问题描述
请注意,此函数没有{和}正文。只是尝试/ catch块:
Note that this function does not have a "{" and "}" body. Just a try/catch block:
void func( void )
try
{
...
}
catch(...)
{
...
}
这是有意的C ++的一部分,还是这是一个g ++扩展?
Is this intentionally part of C++, or is this a g++ extension?
比绕过1级{}?
我从来没有听说过,直到我遇到了 http://stupefydeveloper.blogspot.com/2008/10/c-function-try-catch-block.html
I'd never heard of this until I ran into http://stupefydeveloper.blogspot.com/2008/10/c-function-try-catch-block.html
推荐答案
是的,这是标准的。函数try块,因为它们被调用,不是常用的功能,但对于构造函数,它们允许捕获在初始化列表中抛出的异常。
Yes, it is standard. Function try blocks, as they're called, aren't that much use for regular functions, but for constructors, they allow you to catch exceptions thrown in the initialiser list.
请注意,在构造函数的情况下,异常总是在任何catch块的结尾处重新抛出。
Note that, in the constructor case, the exception will always be rethrown at the end of any catch blocks.
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