作为字符串的当前日期和时间 [英] Current date and time as string

问题描述

我写了一个函数来获取当前日期和时间，格式为： DD-MM-YYYY HH：MM：SS 。它的工作，但让我们说，它漂亮的丑陋。

I wrote a function to get a current date and time in format: DD-MM-YYYY HH:MM:SS. It works but let's say, its pretty ugly. How can I do exactly the same thing but simpler?

string currentDateToString()
{
    time_t now = time(0);
    tm *ltm = localtime(&now);

    string dateString = "", tmp = "";
    tmp = numToString(ltm->tm_mday);
    if (tmp.length() == 1)
        tmp.insert(0, "0");
    dateString += tmp;
    dateString += "-";
    tmp = numToString(1 + ltm->tm_mon);
    if (tmp.length() == 1)
        tmp.insert(0, "0");
    dateString += tmp;
    dateString += "-";
    tmp = numToString(1900 + ltm->tm_year);
    dateString += tmp;
    dateString += " ";
    tmp = numToString(ltm->tm_hour);
    if (tmp.length() == 1)
        tmp.insert(0, "0");
    dateString += tmp;
    dateString += ":";
    tmp = numToString(1 + ltm->tm_min);
    if (tmp.length() == 1)
        tmp.insert(0, "0");
    dateString += tmp;
    dateString += ":";
    tmp = numToString(1 + ltm->tm_sec);
    if (tmp.length() == 1)
        tmp.insert(0, "0");
    dateString += tmp;

    return dateString;
}

推荐答案

：使用< ctime> 标头，您可以使用 strftime 。请确保您的缓冲区足够大，您不会想要超过它并稍后造成严重破坏。

Non C++11 solution: With the <ctime> header, you could use strftime. Make sure your buffer is large enough, you wouldn't want to overrun it and wreak havoc later.

#include <iostream>
#include <ctime>

int main ()
{
  time_t rawtime;
  struct tm * timeinfo;
  char buffer[80];

  time (&rawtime);
  timeinfo = localtime(&rawtime);

  strftime(buffer,80,"%d-%m-%Y %I:%M:%S",timeinfo);
  std::string str(buffer);

  std::cout << str;

  return 0;
}

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