将char []的数组转换为byte []，反之亦然？ C ++ [英] Convert array of char[] to byte[] and vice versa? C++

问题描述

将字符数组转换为字节的最佳方法是什么？

What is the best way to convert an array of chars to bytes and vice versa?

解决方案：

void CharToByte(char* chars, byte* bytes, unsigned int count){
    for(unsigned int i = 0; i < count; i++)
    	bytes[i] = (byte)chars[i];
}

void ByteToChar(byte* bytes, char* chars, unsigned int count){
    for(unsigned int i = 0; i < count; i++)
    	 chars[i] = (char)bytes[i];
}

推荐答案

少数几种具有由ANSI标准保证的大小的类型，并且该大小是1字节。据我所知C不直接定义类型字节。然而，只是没有疯狂的有一个类型命名的字节，事实上不是一个字节的大小。因此，一个简单的施法应该做的伎俩。

The type char is one of the few types that has a size guaranteed by the ANSI standard and that size is 1 byte. As far as I know C does not directly define the type byte. However it would be just short of insane to have a type named byte which is not in fact a byte in size. Therefore a simple cast should do the trick.

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