C ++的析构函数类似接口的类 [英] Destructors for C++ Interface-like classes

问题描述

开始在现有代码库（恐惧和恐惧）上使用PC-Lint。

它抱怨的一件事是：

  class IBatch 
 {
 public：
 virtual void StartBatch（）= 0; 
 virtual int CommitBatch（）= 0; 
}; 
 

当另一个类派生时使用它像接口一样使用它

 基类'IBatch'没有析构函数
  

所以，问题：当你创建类似上面的接口类，你总是包括一个虚拟析构函数？为什么？ （是风格还是编码错误？）

编辑：应该说我不期望或希望IBatch的用户破坏，它们是一个服务的消费者，通过这个接口到一些外部实现类（如果这将有所作为）

解决方案

blockquote>

基类析构函数应该是public和virtual，或受保护和非虚拟。

（Herb Sutter，Guru of the Week＃18：Virtuality）

Starting to use PC-Lint on an existing code base (fear and trepidation).

One thing that it complains about is the following:

 class IBatch
 {
 public:
    virtual void StartBatch() =0;
    virtual int CommitBatch() =0;
 };

Which when another class derives from this to use it like an interface

base class 'IBatch' has no destructor

So, the question: when you create Interface classes like the above, do you always include a virtual destructor? Why? (is it a style or a coding error?)

EDIT: Should have said that I do not expect or want the user of IBatch to destruct, they are a consumer of a service only, through this interface to some external implementing class (if that would make a difference)

解决方案

A base class destructor should be either public and virtual, or protected and nonvirtual.

(Herb Sutter, Guru of the Week #18: "Virtuality")

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