从C ++（STL）中的（其）迭代器类型获取容器类型 [英] Obtain container type from (its) iterator type in C++ (STL)
问题描述
很容易给定一个容器来获取关联的迭代器，例如：
It is easy given a container to get the associated iterators, example:
std::vector<double>::iterator i; //An iterator to a std::vector<double>
我想知道是否可能，给定一个迭代器类型，容器（这里我假设每个容器只有一个（非const）迭代器）。
I was wondering if it is possible, given an iterator type, to deduce the type of the "corresponding container" (here I am assuming that for each container there is one and only one (non-const) iterator).
更准确地说，我想要一个模板元功能与所有STL容器一起工作（不必为每个单个容器手动专门化），例如：
More precisely, I would like a template metafunction that works with all STL containers (without having to specialize it manually for each single container) such that, for example:
ContainerOf< std::vector<double>::iterator >::type
evaluates to
std::vector<double>
有可能吗？
如果没有，为什么？
Is it possible? If not, why?
感谢您提供任何帮助。
推荐答案
我不认为这是可能的。在一些STL库上，你实际上有一个向量迭代器作为指针类型，即。 std :: vector< T> :: iterator是一个T * 所以我不能以任何方式回到容器类型。
I don't think this would be possible. On some STL libraries you actually have a vector iterator as a pointer type, i.e. std::vector<T>::iterator is a T* so I can't think of any way you could get back to the container type from that.
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