如何传递一个字符串的向量到execv [英] How to pass a vector of strings to execv

问题描述

我发现，建立我的程序参数列表的最简单的方法是作为一个字符串的向量。但是，execv期望第二个参数的字符数组。

I have found that the easiest way to build my program argument list is as a vector of strings. However, execv expects an array of chars for the second argument. What's the easiest way to get it to accept of vector of strings?

推荐答案

execv（）只接受一个字符串指针数组。没有办法让它接受别的东西。这是一个标准的接口，可以从每个托管语言调用，而不只是C ++。

execv() accepts only an array of string pointers. There is no way to get it to accept anything else. It is a standard interface, callable from every hosted language, not just C++.

我已经测试编译这个：

    std::vector<string> vector;
    const char *programname = "abc";

    const char **argv = new const char* [vector.size()+2];   // extra room for program name and sentinel
    argv [0] = programname;         // by convention, argv[0] is program name
    for (int j = 0;  j < vector.size()+1;  ++j)     // copy args
            argv [j+1] = vector[j] .c_str();

    argv [vector.size()+1] = NULL;  // end of arguments sentinel is NULL

    execv (programname, (char **)argv);

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