函数名__func__的预定义宏 [英] Predefined Macros for function name __func__

问题描述

我正在尝试构建一个调试日志消息函数，记录调用日志消息的文件，行和函数。

  #define DEBUG_PANIC（p）CLogging :: Debuglogf（Debug marker（％s） -  ::％s文件：％s（％d），p，__func__，__FILE__，__LINE__）; 
  

上述代码适用于某些编译器，但不是全部。我的代码需要与GCC以及Microsoft Visual studio交叉兼容。我已经添加了以下定义来帮助兼容性。

  #ifndef __FUNCTION_NAME__ 
 #if defined __func__ 
 //未声明
 #define __FUNCTION_NAME__ __func__ 
 #elif defined __FUNCTION__ 
 //未声明
 #define __FUNCTION_NAME__ __FUNCTION__ 
 #elif已定义__PRETTY_FUNCTION__ 
 //未声明
 #define __FUNCTION_NAME__ __PRETTY_FUNCTION__ 
 #else 
 //已声明
 #define __FUNCTION_NAME__N / A
 #endif // __func__ 
 
 #endif // __FUNCTION_NAME__ 
 
 #define DEBUG_PANIC（p）CLogging :: Debuglogf（Debug marker（％s） -  ::％s（）in file：％s（％d），p，__FUNCTION_NAME__，__FILE__，__LINE__）; 
  

上述代码片段的问题是#else宏在所有编译器上都是活动的其他宏不是。换句话说， #if defined __func __ 在编译器上为false，其中 __ func __ 是一个预定义的宏 。

我的问题是

• 如何创建交叉编译器宏找到函数名？


• 如何判断是否可以使用 __ func __ ？

解决方案

您假设 __ func __ 是一个宏，但它不是。这是一个有条件支持的预定义标识符，因此您不能使用 #if defined 或 #ifdef 检查它。 / p>

如果编译器没有办法告诉你这是否支持（他们可以通过 _FUNC_SUPPORTED

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b
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  #ifndef __FUNCTION_NAME__ 
 #ifdef WIN32 // WINDOWS 
 #define __FUNCTION_NAME__ __FUNCTION__ 
 #else // * NIX 
 #define __FUNCTION_NAME__ __func__ 
 #endif 
 #endif 
  

I am attempting to build a debug log message function that records the file, line, and function of of where the log message was called from.

#define DEBUG_PANIC(p) CLogging::Debuglogf( "Debug marker (%s) - ::%s() in file: %s(%d)", p, __func__ , __FILE__, __LINE__ );

The above code works on some compilers but not all. My code needs to be cross compatible with GCC as well as Microsoft Visual studios. I have added the below defines to help with compatibility.

#ifndef __FUNCTION_NAME__
    #if defined __func__ 
        // Undeclared 
        #define __FUNCTION_NAME__   __func__ 
    #elif defined __FUNCTION__ 
        // Undeclared
        #define __FUNCTION_NAME__   __FUNCTION__  
    #elif defined __PRETTY_FUNCTION__
        // Undeclared
        #define __FUNCTION_NAME__   __PRETTY_FUNCTION__
    #else
        // Declared
        #define __FUNCTION_NAME__   "N/A"   
    #endif // __func__ 

#endif // __FUNCTION_NAME__

#define DEBUG_PANIC(p) CLogging::Debuglogf( "Debug marker (%s) - ::%s() in file: %s(%d)", p, __FUNCTION_NAME__, __FILE__, __LINE__ );

The problem with the above code snippet is that it is the #else macro is active on all compilers while the other macros are not. in other words #if defined __func__ is false on compilers where __func__ is a predefined macro.

My question is

• How do I create a cross compiler macro to find the function name ?
• How can I tell if a __func__ can be used?

解决方案

You're assuming __func__ is a macro, but it's not. It's a conditionally-supported predefined identifier, so you can't check it with #if defined or #ifdef.

If the compilers have no way of telling you whether this is supported (they could via a _FUNC_SUPPORTED or something, I'm not saying they actually are doing this), you'll have to check the compiler instead of the actual identifier.

Something along the lines:

#ifndef __FUNCTION_NAME__
    #ifdef WIN32   //WINDOWS
        #define __FUNCTION_NAME__   __FUNCTION__  
    #else          //*NIX
        #define __FUNCTION_NAME__   __func__ 
    #endif
#endif

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