将数组作为带有默认值的参数传递到int main（） [英] Passing an array as a parameter with default values into int main()

问题描述

我无法将数组作为参数传递给具有默认值的 int main（）。
例如：

  int main（int a）{} 
  

奇妙。

  int main（int a = 1）{} 
  

传递 int main（）数组也非常奇妙：

  int main（int a [3]）
  

但是，合并这两个概念似乎是：

  int main（int a [1] {0,1}）
  

在大量的 googleing ，我没有找到解决方案。 >

请帮助我这是你唯一的希望！

EDIT

简而言之，目的是为了使我的代码尽可能少的线路，对于我的教授最近发布的挑战（不是为了学习）。该任务是创建递归的12天的圣诞节计划

这是我当前的计划

  #include< iostream> 
 #include< string> 
 void p（std :: string v）{std :: cout<  std :: string v [13] = {梨树中的鹧鸪\\ n，2 Turtle Doves \\\
，3 French Hens \\\
，4 Colly Birds \\\
，5 Gold Rings\\\
，6 Geese-a-Laying\\\
 ，7，9，9，9，9等。 Piping \\\
，12 Drummers Drumming \\\
，}; 
 int main（）{
 switch（v [12] .length（））{
 case 12：system（pause）; return 0; 
 case 11：p（v [11]）; 
 case 10：p（v [10]）; 
 case 9：p（v [9]）; 
 case 8：p（v [8]）; 
 case 7：p（v [7]）; 
 case 6：p（v [6]）; 
 case 5：p（v [5]）; 
 case 4：p（v [4]）; 
 case 3：p（v [3]）; 
 case 2：p（v [2]）; 
 case 1：p（v [1]）; 
 case 0：p（v [0]）; 
} v [12] + =0; 
 main（）; 
} 
  

我想将数组的经文作为参数传递给main在函数上面声明它。我知道，不是最内存/堆栈意识。但它会消除一行：）

解决方案

此链接最好地解释：

在C ++中不可能传递
完整的内存块作为一个
参数到一个函数，但我们是
允许传递其地址。

这就是为什么你可以声明一个函数

  void foo（int bar []）; 
  

但您不能声明

  void foo（int bar [] = {0，1}）; 
  

与 main（）无关。

I am having difficulty passing an array as an argument into int main() with default values. For example:

int main(int a){}

works wonderfully. As does

int main(int a = 1){}

Passing int main() an array also works wonderfully:

int main(int a[3])

However, combining these two concepts seems break:

int main(int a[1] = {0,1})

After a significant amount of googleing, I haven't found a solution.

please help me SO, you're my only hope!

EDIT

The purpose of this, in short, is to make my code as little lines as possible, for a challenge my professor recently issued (not for points -- just for learning). The assignment is to create a recursive "12-days-of-chirstmas" program

This is my current program

#include <iostream> 
#include <string>
void p(std::string v){std::cout<<v;}
std::string v[13] = {"A Partridge in a Pear Tree.\n\n","2 Turtle Doves\n","3 French Hens\n","4 Colly Birds\n","5 Gold Rings\n","6 Geese-a-Laying\n","7 Swans-a-Swimming\n","8 Maids-a-Milking\n","9 Ladies Dancing\n","10 Lords-a-Leaping\n","11 Pipers Piping\n","12 Drummers Drumming\n",""};
int main(){
    switch(v[12].length()){
        case 12:system("pause"); return 0;
        case 11:p(v[11]);
        case 10:p(v[10]);
        case 9: p(v[9]);
        case 8: p(v[8]);
        case 7: p(v[7]);
        case 6: p(v[6]);
        case 5: p(v[5]);
        case 4: p(v[4]);
        case 3: p(v[3]);
        case 2: p(v[2]);
        case 1: p(v[1]);
        case 0: p(v[0]); 
    }v[12] += "0";
    main();
}

I would like to pass in the array of verses as an argument to main instead of declaring it above the function. I know, not the most memory/stack conscious. But it would eliminate a line :)

解决方案

This link explains it best:

In C++ it is not possible to pass a complete block of memory by value as a parameter to a function, but we are allowed to pass its address.

That's why you can declare a function with

void foo (int bar[]);

but you can't declare

void foo (int bar[] = {0 ,1});

It has nothing to do with main().

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