C ++将mac id字符串转换为uint8_t数组 [英] C++ converting a mac id string into an array of uint8_t

问题描述

我想从命令行读取一个mac id，并将其转换为 uint8_t 值的数组，以在结构中使用它。我不能让它工作。我有一个向量的字符串的mac id拆分约：，我想使用 stringstream 运气。

I want to read a mac id from command line and convert it to an array of uint8_t values to use it in a struct. I can not get it to work. I have a vector of string for the mac id split about : and I want to use stringstream to convert them with no luck. What I am missing?

int parseHex(const string &num){
  stringstream ss(num);
  ss << std::hex;
  int n;
  ss >> n;  
  return n;
}

uint8_t tgt_mac[6] = {0, 0, 0, 0, 0, 0};
  v = StringSplit( mac , ":" );
  for( int j = 0 ; j < v.size() ; j++ ){
    tgt_mac[j] = parseHex(v.at(j)); 
  }

推荐答案

这种方式，但 sscanf（）可能是最简洁的方法来解析出一个MAC地址。它处理零/非零填充，宽度检查，大小写折叠和所有其他的东西，没有人喜欢处理。无论如何，这里是我不是那么C ++版本：

I hate to answer this in this fashion, but sscanf() is probably the most succinct way to parse out a MAC address. It handles zero/non-zero padding, width checking, case folding, and all of that other stuff that no one likes to deal with. Anyway, here's my not so C++ version:

void
parse_mac(std::vector<uint8_t>& out, std::string const& in) {
    unsigned int bytes[6];
    if (std::sscanf(in.c_str(),
                    "%02x:%02x:%02x:%02x:%02x:%02x",
                    &bytes[0], &bytes[1], &bytes[2],
                    &bytes[3], &bytes[4], &bytes[5]) != 6)
    {
        throw std::runtime_error(in+std::string(" is an invalid MAC address"));
    }
    out.assign(&bytes[0], &bytes[6]);
}

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