随机长生成器C ++ [英] Random long long generator C++

问题描述

什么是生成随机 long long 和加密强度С++的解决方案？ （允许提升）

What is a solution to generate random long long with cryptographic strength С++? (boost is allowed)

推荐答案

< random> 便携式访问随机数设施，包括可能的加密pRNG。

The <random> header provides portable access to random number facilities including, potentially, a cryptographic pRNG.

#include <random>     // random_device, uniform_int_distribution
#include <algorithm>  // generate_n
#include <iterator>   // ostream_iterator
#include <iostream>   // cout
#include <functional> // bind, ref

int main() {
    std::random_device r;
    std::uniform_int_distribution<long long> dist;

    std::generate_n(std::ostream_iterator<long long>(std::cout, "\n"), 10,
        std::bind(dist,std::ref(r)));
}

std :: random_device 可能不是所有实现上的加密pRNG，因此您必须检查实现文档。特别是2012年之前的VC ++不提供非确定性的实现。

std::random_device may not be a cryptographic pRNG on all implementations, so you'll have to check your implementation documentation. In particular VC++ before 2012 does not provide a non-deterministic implementation. VC++ 2012 and later implements this using Windows cryptography services.

其他操作系统（如Linux或Mac OS X）上的实现通常可以使用/ dev / urandom dev / random或通过文件系统公开的任何其他随机设备。例如。 libc ++默认使用/ dev / urandom，在OS X上使用Yarrow算法。

Implementations on other operating systems such as Linux or Mac OS X can commonly use "/dev/urandom" or "/dev/random" or any other random device exposed via the filesystem. E.g. libc++ uses "/dev/urandom" by default, which on OS X uses the Yarrow algorithm.

我知道你排除了boost，但 boost :: random_device 具有使用该平台的加密服务的Windows实现。

I know you ruled out boost, but boost::random_device has an implementation for Windows that uses that platform's cryptography services.

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