默认虚拟设备 [英] default virtual d'tor

问题描述

让我们假设我有两个类：

Let us assume I have two classes:

class Base{};

class Derived: public Base{};

none has d'tor，在这种情况下，如果我声明关于变量：

none has d'tor, in this case if I declare about variables:

Base b;
Derived d;

我的编译器会为我生成，我的问题是，默认的 b和d 是否为虚拟？

my compiler will produce for me d'tors, my question is, the default d'tors of the b and d will be virtual or not?

推荐答案

我的问题是，b和d的对象将是虚拟的

my question is, the d'tors of the b and d will be virtual or not

t。如果你想要一个虚拟析构函数，你必须定义你自己的，即使它的实现与编译器提供的完全一样：

No, they won't. If you want a virtual destructor, you will have to define your own, even if its implementation is exactly the same as that which would be supplied by the compiler:

class Base {
  public:
    virtual ~Base() {}
};

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