对于已编码的简单函数，发生分段故障错误 [英] Segmentation fault error occurs for a simple function I have coded

问题描述

这里我只想定义一个返回矩阵乘法的函数， N 任意，我想生成一个 new 命令。当我执行该函数时，我得到错误：

Here I just want to define a function which returns the multiplication of matrices, with N arbitrary, I would like to generate a matrix with a new command. When I execute the function I get the error:

Segmentation fault (core dumped)

每当我为 C 赋值时，我就有这个错误，任何人都能告诉我发生了什么，如何修复它？

Whenever I assign values to C I have this error, could anybody tell me what happened and how to fix it?

int **multiply(int **A, int **B, int N){
    int **C = new int*[N];
    for (int i = 0; i < N; i++) {
        for (int j = 0; j < N; j++) {
            for (int k = 0; k < N; k++)
                C[i][j] = C[i][j] + A[i][k] * B[k][j];
        }
    }
    return (C);
}

推荐答案

int **C=new int*[N];

这会为指针数组创建空间。它不会初始化它们，所以他们可以指向任何地方。它们可能是NULL指针。

This makes space for an array of pointers. It doesn't initialize them, so they could point anywhere. They might even be NULL pointers.

C[i][j]

这可能会导致空指针取消引用。这可能是造成分段错误的原因。

This might cause a null pointer dereference. That's probably what causes the segmentation fault.

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