如何很好地输出分隔的字符串列表？ [英] How to nicely output a list of separated strings?

问题描述

通常，当我不得不显示一个单独的字符串列表时，我是这样做的：

Usually, when I had to display a list of separated strings, I was doing something like:

using namespace std;
vector<string> mylist; // Lets consider it has 3 elements : apple, banana and orange.

for (vector<string>::iterator item = mylist.begin(); item != mylist.end(); ++item)
{
  if (item == mylist.begin())
  {
    cout << *item;
  } else
  {
    cout << ", " << *item;
  }
}

哪些输出：

apple, banana, orange

我最近发现了 std :: ostream_iterator ，如果发现真的很好用。

I recently discovered std::ostream_iterator which if found really nice to use.

但是使用下面的代码： / p>

However with the following code:

copy(mylist.begin(), mylist.end(), ostream_iterator<string>(cout, ", "));

如果获得：

apple, banana, orange, 

几乎完美， c $ c>，。有没有一种优雅的方式来处理特殊的第一（或最后）元素情况，并具有相同的输出比第一个代码，没有它的复杂性？

Almost perfect, except for the extra ,. Is there an elegant way to handle the special "first (or last) element case" and to have the same output than the first code, without its "complexity" ?

推荐答案

虽然不是std：

cout << boost::algorithm::join(mylist, ", ");

编辑：没问题：

cout << boost::algorithm::join(mylist | 
    boost::adaptors::transformed(boost::lexical_cast<string,int>), ", "
);

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