如何从函数返回数组并循环通过它？ [英] How to return an array from a function and loop through it?

问题描述

  #include< iostream> 
 
 int * fib（int）; 
 
 int main（）
 {
 int count; 
 std :: cout<<输入要打印斐波那契数列的数字<< std :: endl; 
 std :: cin>> count; 
 int * p = new int [count]; 
 p = fib（count）; 
 int i; 
 for（i <0; i <= count; i ++）
 std :: cout 
 return 0; 
} 
 
 int * fib（int d）
 {
 int * ar = new int [d] 
 int p = -1，q = 1，r; 
 int j; 
 for（j = 0; j <= d; j ++）
 {
 r = p + q; 
 ar [j] = r; 
 p = q; 
 q = r; 
} 
 return ar; 
 delete ar; 
} 
  

为什么我无法以这种方式打印整个Fibonacci数组

解决方案

您的代码有几个问题

 code> for（i <0; i <= count; i ++）
  

  for（i = 0; i    
 
 
和
  ; j ++）
  
必须读
  for（j = 0; j< d; j ++）
  
删除该行
  delete ar; 
  
因为它在返回后没有任何效果语句。此外，你可以摆脱实例化
  int * p = new int [count] $ c $ b   
在 fib 函数中。因为它是，你泄漏你刚刚分配的记忆。
 
#include <iostream>

int* fib(int);

int main()
{
    int count;
    std::cout<<"enter number up to which fibonacci series is to be printed"<<std::endl;
    std::cin>>count;
    int *p=new int[count];
    p=fib(count);
    int i;
    for(i<0;i<=count;i++)
        std::cout<<p[i]<<std::endl;
    return 0;
}

int* fib(int d)
{
    int *ar=new int[d];
    int p=-1,q=1,r;
    int j;
    for(j=0;j<=d;j++)
    {
        r=p+q;
        ar[j]=r;
        p=q;
        q=r;
    }
    return ar;
    delete ar;
}
Why am I not able to print the whole array of Fibonacci series in this way?
解决方案
Several issues with your code
for(i<0;i<=count;i++)
should actually be
for(i=0;i<count;i++)
and
for(j=0;j<=d;j++)
must read
for(j=0;j<d;j++)
And remove the line
delete ar;
since it does not have any effect after the return statement. Additionally you can get rid of the instantiation
int *p=new int[count];
in main() since this is done in your fib function also.  As it stands, you leak the memory you just allocated.

                        
这篇关于如何从函数返回数组并循环通过它？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！