不兼容的类型 - 是因为数组已经是一个指针了? [英] Incompatible types - is it because an array is already a pointer?
问题描述
在下面的代码中,我创建一个基于书籍结构的对象,并且它拥有多个书籍我设置是一个数组(被定义/启动的对象)。但是,每当我去测试我的指针知识(实践帮助),并试图做一个指针指向创建的对象,它给我的错误:
In the below code I create an object based off of the books structure, and to have it hold multiple "books" I set is an array (the object that is defined/initiated, that is). However, whenever I went to test my knowledge of pointers (the practice helps) and attempted to make a pointer that points to the created object, it gives me the error:
C:\Users\Justin\Desktop\Project\wassuip\main.cpp | 18 |错误:将书籍分配给books * [4]时不兼容的类型| *
C:\Users\Justin\Desktop\Project\wassuip\main.cpp|18|error: incompatible types in assignment of 'books' to 'books* [4]'|*
我可以问,这是因为对象book_arr []已经被认为是一个指针,因为它是一个数组?感谢(新到C ++,只想验证)。
May I ask, is this because the object book_arr[] is already considered a pointer as it's an array? Thanks (new to C++ and just want to verify).
#include <iostream>
#include <vector>
#include <sstream>
#define NUM 4
using namespace std;
struct books {
float price;
string name;
int rating;
} book_arr[NUM];
int main()
{
books *ptr[NUM];
ptr = &book_arr[NUM];
string str;
for(int i = 0; i < NUM; i++){
cout << "Enter book name: " << endl;
cin >> ptr[i]->name;
cout << "Enter book price: " << endl;
cin >> str;
stringstream(str) << ptr[i]->price;
cout << "Enter book rating: " << endl;
cin >> str;
stringstream(str) << ptr[i]->rating;
}
return 0;
}
* 答案后的新代码(无错误)*
#include <iostream>
#include <vector>
#include <sstream>
#define NUM 4
using namespace std;
/* structures */
struct books {
float price;
string name;
int rating;
} book[NUM];
/* prototypes */
void printbooks(books book[NUM]);
int main()
{
string str;
books *ptr = book;
for(int i = 0; i < NUM; i++){
cout << "Enter book name: " << endl;
cin >> ptr[i].name;
cout << "Enter book price: " << endl;
cin >> str;
stringstream(str) << ptr[i].price;
cout << "Enter book rating: " << endl;
cin >> str;
stringstream(str) << ptr[i].rating;
}
return 0;
}
void printbooks(books book[NUM]){
for(int i = 0; i < NUM; i++){
cout << "Title: \t" << book[i].name << endl;
cout << "Price: \t$" << book[i].price << endl;
cout << "Racing: \t" << book[i].rating << endl;
}
}
推荐答案
img src =http://i.imgur.com/Zwhdn.gifalt =数组不是指针>
请参阅如何在C ++中使用数组?详细信息。
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