auto在c ++ 11是静态类型或动态类型 [英] auto in c++11 is static typing or dynamic typing

问题描述

c ++ 11中的auto命令是静态绑定（打字）还是动态绑定？

如果我有这个代码

  auto x = 5; 
  

编译器会确定x是一个int还是将在运行时解析？ / p>

此外，以下代码中x的类型是什么？

  auto x = 5，y = 4.5 
  

解决方案

称为类型推断。输入仍然是 static ，但是让编译器确定表达式的类型。

具体 auto x = 5; ，在编译时，翻译为 int x = 5; 。因为这个原因，你总是在初始化时提供一个明确的表达式。例如 auto x; 无法工作。

Is auto command in c++11 is static binding(typing) or dynamic binding?

i.e. if i have this code

auto x = 5;

will the compiler decide that "x" is a int, or will it be descovered on runtime?

also, what will be the type of x in the following code?

auto x = 5, y = 4.5

解决方案

This is called type inference. The typing is still static, but you leave the compiler figure out what the type of an expression is.

Specifically auto x = 5;, at compiler time, is translated to int x = 5;. For this very reason you have always to provide an unambiguous expression at initialization. For example auto x; wouldn't work.

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