C ++局部变量销毁顺序 [英] C++ local variable destruction order

问题描述

有一个定义的顺序，其中局部变量在C ++（11）中释放？
为了更简洁：在同一范围内两个局部变量的析构函数的副作用将变得可见。

例如：

  struct X {
〜X（）{/ * do something * /} 
} 
 
 int main（）{
 X x1; 
 X x2; 
 return 0; 
} 
  

是 x1

解决方案 x2 在主返回时首先销毁或是在C ++ 11中未定义的订单？ div>

在每个类别的存储类（动态分配的对象除外）中，对象以与构造相反的顺序被破坏。

Is there a defined order in which local variables are deallocated in C++ (11) ? To be more concise: In which order will side effects of the destructors of two local variables in the same scope become visible?

e.g.:

struct X{
  ~X(){/*do something*/}
}

int main(){
   X x1;
   X x2;
   return 0;
}

Is x1 or x2 destroyed first when main returns or is the order undefined in C++11?

解决方案

Within each category of storage classes (except dynamically alloated objects), objects are destructed in the reverse order of construction.

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