获取源代码背后clang的AST [英] Getting the source behind clang's AST

问题描述

在clang中给定一个AST对象，我如何获取它的代码？我尝试编辑教程中的代码，并添加了：

Given an AST object in clang, how can I get the code behind it? I tried editing the code in the tutorial, and added:

clang::SourceLocation _b = d->getLocStart(), _e = d->getLocEnd();
char *b = sourceManager->getCharacterData(_b),
      e = sourceManager->getCharacterData(_E);
llvm:errs() << std::string(b, e-b) << "\n";

但是唉，它没有打印整个typedef声明，只有大约一半！打印 Expr 时会出现同样的现象。

but alas, it didn't print the whole typedef declaration, only about half of it! The same phenomena happened when printing Expr.

如何打印并查看构成声明的整个原始字符串？

How can I print and see the whole original string constituting the declaration?

推荐答案

使用 Lexer 模块：

clang::SourceManager *sm;
clang::LangOptions lopt;

std::string decl2str(clang::Decl *d) {
    clang::SourceLocation b(d->getLocStart()), _e(d->getLocEnd());
    clang::SourceLocation e(clang::Lexer::getLocForEndOfToken(_e, 0, *sm, lopt));
    return std::string(sm->getCharacterData(b),
        sm->getCharacterData(e)-sm->getCharacterData(b));
}

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